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"Time to do my homework"

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Wed 04/05/05 at 21:58
Regular
"0228"
Posts: 5,953
Time for you to do my homework that is.

Simplify:
(5x² + 14x - 3) / (x² - 9)

You know you can do it, I know you can do it, so how about we cut out the 'google it noob' stuff and somebody just helps me out, please.

Thanks in advance for any help.

Yeah, I'm thick, I can't do simple maths
Thu 05/05/05 at 22:31
Regular
"Too Orangy For Crow"
Posts: 15,844
Well done down and Clazon. When I tried to work it out, I couldn't, but then I haven't done anything like this in almost 8 years.
Thu 05/05/05 at 22:28
"period drama"
Posts: 19,792
Aye, godly things.
Thu 05/05/05 at 22:24
Regular
"bit of a brain"
Posts: 18,933
I thought simultaneous equations were great.
Thu 05/05/05 at 22:22
"period drama"
Posts: 19,792
Ah, of course, the curséd quadratic factorisation.
Forgot it even existed.

Still, simultaneous equations rule all.
Thu 05/05/05 at 22:15
Posts: 4,686
Yah? Check first page, loooooser.
:-p
Thu 05/05/05 at 20:28
"slightlyshortertagl"
Posts: 10,759
Yuh, well done Niddle for getting the answer right first.

Well done.

:-P
Thu 05/05/05 at 20:19
Regular
"The Red Shift"
Posts: 6,807
(5x² + 14x - 3)
_________________

(x² - 9)



Step one- top line- quadratic factorisation:

(5x + 15) (5x - 1)
________

5

= (x + 3) (5x - 1)


Step two- bottom line- a difference of 2 squares:

*root* x and *root* 9

= (x - 3) (x + 3)


Step three- combining them

(x + 3) and (x + 3) cancel.

Thus:

(5x - 1)
_________

(x - 3)




EDIT:

Damn you down.
Thu 05/05/05 at 20:11
Posts: 4,686
(5x² + 14x - 3) / (x² - 9)
= [(5x-1)(x+3)] / [(x-3)(x+3)]
= (5x-1) / (x-3)

The / is a divisive sign, not an equals as some people seem to have confused it with.
Thu 05/05/05 at 19:55
Regular
"Monochromatic"
Posts: 18,487
Screw it
Thu 05/05/05 at 19:54
"slightlyshortertagl"
Posts: 10,759
Answer

(5x - 1) / (x-3)

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