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I rarely ask for help from you gaylords, because the truth is, the majority of you are idiots.
Anyway, that's the flattery out of the way...
Physics - the subject of joy. I'm stuck on this question.
It's worth 3 marks. Anyway;
"The resistance of a length of bare uniform resistance wire is 30 ohms. The length of wire is folded into the shape of a square and the ends soldered together as shown below
(a picture of a square with an ohmmeter connected to it) - [URL]http://firestorm.staghosting.com/image.jpg[/URL]
What value of resistance would the ohmmeter read if it is connected as shown at the mid-points of opposite sides to the square?
(You may ignore the resistance of the ohmmeter leads)"
***
Cheers for any help people - I'm honestly at a loss.
And merm, if you claim it's 600 joules, I will hit you.
The resistance is still 30 ohms there, it's just a wire joined together.
There is no resistance then, there's no power supply.
> Hmm.
>
> 7.5 Ohms
>
> Resistances in parallel. 1/15 + 1/15 = 2/15. Invert. 15/2 = 7.5
>
> But then it's been about 10 years since I last did phyciscs or
> electronic engineering, so I take no responsibility.
Theres no componenets, so therefor no parallels or series'. That only applied for components.
> What is an A at your uni?
90-100%
A+ - 100%
A - 95%
A- - 90%
And so forth.
> Hmm.
>
> 7.5 Ohms
>
> Resistances in parallel. 1/15 + 1/15 = 2/15. Invert. 15/2 = 7.5
Can you please explain this in detail, im intrested.