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Trying to do maths homework (revision) I cannot do it and I have wund myself up into a state where I 'know' I am going to fail my GCSE and work in Burger King for the rest of my life, any help would be appreciated if you show me how you got the answers, thanks.
1. Find correct to 2 decimal places, the solutions of the equation
x² - 3x – 3 = 0
You must show working, do not use trial and improvement method
10 a) Calculate 651.6 – 4.02 / 7 – 8.2²
10 b) Using indices, write 392 as a product of its prime factors
12 a) solve the equation “6(x + 2) = 2x – 6
12 c) Make “d” the subject of the formula
S = ½ xd²
1. Find correct to 2 decimal places, the solutions of the equation
x² - 3x – 3 = 0
You must show working, do not use trial and improvement method
10 a) Calculate 651.6 – 4.02 / 7 – 8.2²
10 b) Using indices, write 392 as a product of its prime factors
12 a) solve the equation “6(x + 2) = 2x – 6
12 c) Make “d” the subject of the formula
S = ½ xd²
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BEARDS. wrote:
> You could just be stupid.
I knowt stoopid!
I got an A* in my maths coursework, perhaps because I can write well but I must have done pretty good and understood maths at that time, I have jsut lost it now. Plus the teacher is senile.
> You could just be stupid.
I knowt stoopid!
I got an A* in my maths coursework, perhaps because I can write well but I must have done pretty good and understood maths at that time, I have jsut lost it now. Plus the teacher is senile.
mäddmuñ wrote:
> Parr wrote:
>
> (X - 3)(X + 1) = 0 (start by factorising)
>
> Multiply that out, and it's wrong, use the quadratic formula for it.
>
> x = -b +/- the square root of (b squared - 4ac)
>
> THen, all of the above line, divided by 2a.
>
> If I remember correctly, I haven't used it since my prelim in
> December.
yeah thats correct with the 4ac
> Parr wrote:
>
> (X - 3)(X + 1) = 0 (start by factorising)
>
> Multiply that out, and it's wrong, use the quadratic formula for it.
>
> x = -b +/- the square root of (b squared - 4ac)
>
> THen, all of the above line, divided by 2a.
>
> If I remember correctly, I haven't used it since my prelim in
> December.
yeah thats correct with the 4ac
You could just be stupid.
Thanks for all your help, I dont understand half of the questions still so I will go see my teacher, it is her job for me to understand, and if I dont then she isn't doing her job right.... right?
infact, 2ac is actually 4ac
Parr wrote:
> (X - 3)(X + 1) = 0 (start by factorising)
Multiply that out, and it's wrong, use the quadratic formula for it.
x = -b +/- the square root of (b squared - 2ac)
THen, all of the above line, divided by 2a.
If I remember correctly, I haven't used it since my prelim in December.
> (X - 3)(X + 1) = 0 (start by factorising)
Multiply that out, and it's wrong, use the quadratic formula for it.
x = -b +/- the square root of (b squared - 2ac)
THen, all of the above line, divided by 2a.
If I remember correctly, I haven't used it since my prelim in December.
Its not the answers I particularly want, I want to know how to work them out!
I'd find you the answers, but I lack a decent calculator and the effort to do it.
BEARDS. wrote:
> Parr wrote:
> 1. Find correct to 2 decimal places, the solutions of the equation
>
> x2 - 3x – 3 = 0
>
> (X - 3)(X + 1) = 0 (start by factorising)
>
> That multiplies out to give x^2 +x -3x -3 which equals x^2 -2x -3.
>
> You need to use the formula which is something like -b ±
> root(b^2-4ac)/2a
>
OK, now I am lost again :'(
> Parr wrote:
> 1. Find correct to 2 decimal places, the solutions of the equation
>
> x2 - 3x – 3 = 0
>
> (X - 3)(X + 1) = 0 (start by factorising)
>
> That multiplies out to give x^2 +x -3x -3 which equals x^2 -2x -3.
>
> You need to use the formula which is something like -b ±
> root(b^2-4ac)/2a
>
OK, now I am lost again :'(
I made a newbie maths teacher quit our school after a year simply by repeatedly pointing out to her that she was ineffective if you didn't understand the one method she knew how to do things.
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