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It is on vectors and the first question is easy but I don't know what to do for some reason...
Calculate length of vector a:
a = 5i + 2/2j - 4/3k
/ = square root
So what do I do?
> I'm doing maths homework sheet and nearly finished it...
It is on vectors and
> the first question is easy but I don't know what to do for some
> reason...
Calculate length of vector a:
a = 5i + 2/2j - 4/3k
/ = square
> root
So what do I do?]
go to sleep...
TOUCH ME!
Sonic
> value of sin 2A if sin A = 3/4
0
hmmm... this is my worst area of matsh... but hey!
sin2A= 2 * sinA * cosA
sin2A= 2 * (3/4) * cosA
Now, cos sq + sin sq = 1
so cosA = ROOT(1-sin(sq))
cosA = root(7/16)
Since A is between 0 and 2pi, then cosA is positive, so we take the POSITIVE root only!
therefore
sin2A = 2 * (3/4) * (root7)/4
= [6 * ROOT(7)]/16
=3ROOT(7) / 8
Sonic
I think someone got it... but basically it's just pythagoras- take the root of the sum of the squares of each side.
So, 5 sq + 2/2 sq + 4/3 sq = 25 + 8 + 48 = 81
And the length is just the root of this answer = 9
Sonic
I always get the fecking hard ones and forget how to do the simple stuff.
Venom was correct though, answer was 9:
I did it this way
square root of:
i squared
j squared
k squared
and it came out 9... hard to replicate it on keyboard :)
----
Thats me done 12 sides of paper and only 1 more left:
exact value of sin 2A if sin A = 3/4
0
Hmmm
Think I change 3/4 to 3pie/4 then use formula, bah.
If thats what you mean.
They should be. Then its just Pythagorus in three dimensions:
For eg
a = xi + yj + zk
gives length of a to be:
/(x^2 + y^2 + z^2)
/ is sqrt again and x^2 means x squared. Just stick in the values for x, y and z (5, 2/2 and 4/3 in this case)
I wont give you the answer, but it should be a whole number I think.
Any other qu's, I'm always happy to help.