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My first is in biscuit but never in cake
My second's in awesome but not in great
My third is in mother but not seen in dad
My fourth is in sunny but never in sad
My fifth is a vowel found in water not creek
My sixth is found only in one day of the week
My seventh's two of three that you learn when you're young
My eighth's not in song but it's there when it's sung
My ninth's in eleven and twelve, not thirteen
My tenth is in island and river, not stream
My eleventh's in precious and secret and paste
My twelfth is in phantom and spectre and haste
My whole stalks the night in a quiet dreamlike state
With no memories the next day of being out late
My second's in awesome but not in great
My third is in mother but not seen in dad
My fourth is in sunny but never in sad
My fifth is a vowel found in water not creek
My sixth is found only in one day of the week
My seventh's two of three that you learn when you're young
My eighth's not in song but it's there when it's sung
My ninth's in eleven and twelve, not thirteen
My tenth is in island and river, not stream
My eleventh's in precious and secret and paste
My twelfth is in phantom and spectre and haste
My whole stalks the night in a quiet dreamlike state
With no memories the next day of being out late
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Kinda similar to one of the first ones but:
While Christmas shopping I chose a gold ring set with stones for my mother.
A ring set with 2 rubies and a diamond would have cost £3,000. one set with 4 amethysts and a diamond would come to £2,000. And 3 emeralds, 1 amethyst and a diamond would be £1,400.
Being a thoughtful son, I chose a ring that would have sentimental value. As my mother called her children Ellen, David, Richard and Andy, I have chosen a ring with one of each stone, to represent her childrens names.
How much will my ring containing 1 emerald, 1 diamond, 1 ruby and 1 amethyst cost me?
While Christmas shopping I chose a gold ring set with stones for my mother.
A ring set with 2 rubies and a diamond would have cost £3,000. one set with 4 amethysts and a diamond would come to £2,000. And 3 emeralds, 1 amethyst and a diamond would be £1,400.
Being a thoughtful son, I chose a ring that would have sentimental value. As my mother called her children Ellen, David, Richard and Andy, I have chosen a ring with one of each stone, to represent her childrens names.
How much will my ring containing 1 emerald, 1 diamond, 1 ruby and 1 amethyst cost me?
It's old, easy and pathetic but...
This can be seen by the naked eye, is weightless, and when put into a barrel it can make the barrel lighter...
This can be seen by the naked eye, is weightless, and when put into a barrel it can make the barrel lighter...
Thanks for both blue hat explanations. It's quite clever.
Rosalind wrote:
> 672
> 159
> 834
Is indeed the correct answer
> 672
> 159
> 834
Is indeed the correct answer
672
159
834
159
834
Ineedsleep wrote:
> Simon Says wrote:
> Unbeliever wrote:
>
> least one of you is wearing a blue hat. There may be only one blue
> hat
> and two white hats, there may be two blue hats and one white hat, or
> there may be three blue hats. But you may be certain that there are
> not three white hats."
>
> Simon Says wrote:
> If a sage opened his eyes and saw a white and a blue hat then his
> hat
> must also be blue, else there are two white hats and the test would
> not be fair.
>
>
> Unbeliever, first sentence - There may be only one blue hat and two
> white hats.
>
> Okay, you got the right answer but logic seems flawed, or have I
> missed something else? I think I need to go back to work.
I'll try again.
You cannot have three white hats.
If one sage opened his eyes and saw two white hats he would know his hat was blue, therefore if there were one blue hat and two white hats the test would not be fair, so there cannot be two white hats and one blue hat, else the sage with the blue hat would win instantly.
given that is true, if a sage opened his eyes and saw a white hat and a blue hat then his hat must be blue, otherwise another the sage with the blue hat would see two white hats, and know his hat was blue.
Another way of looking at it is that unless all the hats are the same colour, the test cannot be fair. Therefore all hats are blue.
Does that help any.
> Simon Says wrote:
> Unbeliever wrote:
>
> least one of you is wearing a blue hat. There may be only one blue
> hat
> and two white hats, there may be two blue hats and one white hat, or
> there may be three blue hats. But you may be certain that there are
> not three white hats."
>
> Simon Says wrote:
> If a sage opened his eyes and saw a white and a blue hat then his
> hat
> must also be blue, else there are two white hats and the test would
> not be fair.
>
>
> Unbeliever, first sentence - There may be only one blue hat and two
> white hats.
>
> Okay, you got the right answer but logic seems flawed, or have I
> missed something else? I think I need to go back to work.
I'll try again.
You cannot have three white hats.
If one sage opened his eyes and saw two white hats he would know his hat was blue, therefore if there were one blue hat and two white hats the test would not be fair, so there cannot be two white hats and one blue hat, else the sage with the blue hat would win instantly.
given that is true, if a sage opened his eyes and saw a white hat and a blue hat then his hat must be blue, otherwise another the sage with the blue hat would see two white hats, and know his hat was blue.
Another way of looking at it is that unless all the hats are the same colour, the test cannot be fair. Therefore all hats are blue.
Does that help any.
I see what you mean, but i was prepared to give him the benefit of the doubt:
His hat was blue.
This is a true test for the cleverest sage since any one them could have come up with the answer. To show this is the case, consider a situation which we knew was not the case, that there was exactly one blue hat. What would happen? There would be a split second of pondering by the person wearing that hat, and he would say "I am wearing a blue hat" as he can only see two white.
Our sages worked this out for themselves, and so knew there could not be only one blue hat in the game.
This leaves everyone wondering, "Are there two or three blue hats?"
Consider the situation where there were exactly two blue hats. This seems a very real possibility at first, after all, we can see exactly two blue hats. So everyone sits and thinks- for a little while. But if there are only two hats, then two people see one blue and one white hat. These two people will very quickly, by virtue of the other's silence, rule out the possibility that there is only one blue hat (above). One of these two lucky sages would cry blue within a few short minutes, if that long.
There only scenario which forces the three sages to sit in silence is three blue hats. Our sage, through his sharp wits was the first to reach this conclusion.
His hat was blue.
This is a true test for the cleverest sage since any one them could have come up with the answer. To show this is the case, consider a situation which we knew was not the case, that there was exactly one blue hat. What would happen? There would be a split second of pondering by the person wearing that hat, and he would say "I am wearing a blue hat" as he can only see two white.
Our sages worked this out for themselves, and so knew there could not be only one blue hat in the game.
This leaves everyone wondering, "Are there two or three blue hats?"
Consider the situation where there were exactly two blue hats. This seems a very real possibility at first, after all, we can see exactly two blue hats. So everyone sits and thinks- for a little while. But if there are only two hats, then two people see one blue and one white hat. These two people will very quickly, by virtue of the other's silence, rule out the possibility that there is only one blue hat (above). One of these two lucky sages would cry blue within a few short minutes, if that long.
There only scenario which forces the three sages to sit in silence is three blue hats. Our sage, through his sharp wits was the first to reach this conclusion.
Simon Says wrote:
> Unbeliever wrote:
> least one of you is wearing a blue hat. There may be only one blue
> hat
> and two white hats, there may be two blue hats and one white hat, or
> there may be three blue hats. But you may be certain that there are
> not three white hats."
Simon Says wrote:
> If a sage opened his eyes and saw a white and a blue hat then his hat
> must also be blue, else there are two white hats and the test would
> not be fair.
Unbeliever, first sentence - There may be only one blue hat and two white hats.
Okay, you got the right answer but logic seems flawed, or have I missed something else? I think I need to go back to work.
> Unbeliever wrote:
> least one of you is wearing a blue hat. There may be only one blue
> hat
> and two white hats, there may be two blue hats and one white hat, or
> there may be three blue hats. But you may be certain that there are
> not three white hats."
Simon Says wrote:
> If a sage opened his eyes and saw a white and a blue hat then his hat
> must also be blue, else there are two white hats and the test would
> not be fair.
Unbeliever, first sentence - There may be only one blue hat and two white hats.
Okay, you got the right answer but logic seems flawed, or have I missed something else? I think I need to go back to work.
ooops
1-9
Sorry!
1-9
Sorry!
0-9 is ten digits.
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