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Really stuck on maths, can somone help please?
In triangle KLM, angle LKM = 45degrees and angle LMK = 30degrees. Find the exact value of LM/KL.
In triangle KLM, angle LKM = 45degrees and angle LMK = 30degrees. Find the exact value of LM/KL.
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Trigonometry deals with right angled trianges.
A triangle
AngleA = 90 degrees
AngleB = 90 degrees
What is angleC?
AngleA = 90 degrees
AngleB = 90 degrees
What is angleC?
Ooh! It says EXACT value. Does that help?
Maybe you have to write it in like letters and stuff? Like KLMsinLK=Cos45/30. Can you tell I made that up off of the top of my head? But maybe it is something like that.
Maverick42 wrote:
> They could be anything.
Anything within a certain ratio.
> They could be anything.
Anything within a certain ratio.
Sdrawkcab wrote:
> There's no right angle!
>
> Angle LKM (a.k.a. Angle K) is 45 degrees.
> Angle KML (a.k.a. Angle M) is 30 degrees.
> Angle MLK (a.k.a. Angle L) is 105 degrees.
>
> So the line joining Angle L and Angle M is sideLM, and the line
> joining Angle L and Angle K is sideLK.
>
> Does that help?
If you only have those three angles, then the sides have no certain length. They could be anything. Just think that AAA does not prove congruency.
> There's no right angle!
>
> Angle LKM (a.k.a. Angle K) is 45 degrees.
> Angle KML (a.k.a. Angle M) is 30 degrees.
> Angle MLK (a.k.a. Angle L) is 105 degrees.
>
> So the line joining Angle L and Angle M is sideLM, and the line
> joining Angle L and Angle K is sideLK.
>
> Does that help?
If you only have those three angles, then the sides have no certain length. They could be anything. Just think that AAA does not prove congruency.
Maverick42 wrote:
> Then it cannot be done.
It can, advanced Trig
> Then it cannot be done.
It can, advanced Trig
Maverick42 wrote:
> Then it cannot be done.
That's what I thought. I bet you the goddamn teacher typed the question out wrong. Bah humbug.
> Then it cannot be done.
That's what I thought. I bet you the goddamn teacher typed the question out wrong. Bah humbug.
Maverick42 wrote:
> Sdrawkcab wrote:
> In the triangle KLM, angle LKM = 45degrees and angle LMK =
> 30degrees.
> Find the exact value of side LM divided by side LK.
>
> Tell me the sides in terms of their relation to the right angle.
There's no right angle!
Angle LKM (a.k.a. Angle K) is 45 degrees.
Angle KML (a.k.a. Angle M) is 30 degrees.
Angle MLK (a.k.a. Angle L) is 105 degrees.
So the line joining Angle L and Angle M is sideLM, and the line joining Angle L and Angle K is sideLK.
Does that help?
> Sdrawkcab wrote:
> In the triangle KLM, angle LKM = 45degrees and angle LMK =
> 30degrees.
> Find the exact value of side LM divided by side LK.
>
> Tell me the sides in terms of their relation to the right angle.
There's no right angle!
Angle LKM (a.k.a. Angle K) is 45 degrees.
Angle KML (a.k.a. Angle M) is 30 degrees.
Angle MLK (a.k.a. Angle L) is 105 degrees.
So the line joining Angle L and Angle M is sideLM, and the line joining Angle L and Angle K is sideLK.
Does that help?
Then it cannot be done.
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