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Argh... I know what to do, but now I'm stuck with differentiating this;
16(pi)h^3
81
(see what i did there with underlining and fractions? :-P)
I'm stuck. Quite bad.
Help! :-)
> A-level Maths is easy, and I do Further. Thats double what all ye
> A-Level Maths guys are doing.
I do further too........
Most of the stuff you do is also about as useful as having an ass on the back of your head.
> a day with 4 consecutive hours of Maths :(
*explodes*
> Did you get A* at GCSE?
Yup, one of many :P
> Wait a second - I got it wrong. Here's the right answer, and I'll go
> through the 81 bit.
>
> Right, so, something divided by 81 is the same as something
> multiplied by 1 over 81. So in my head I did the differentiation of:
>
> (1/81)(16)(pi)(h^3)
>
> Which is equivalent to:
>
> (16/81)(pi)(h^3)
>
> Which, differentiated in terms of h, becomes:
>
> 3(16/81)(pi)(h^2) = (48/81)(pi)(h^2)
Which should be simplified to 16/27(pi)h²
You could "simplify" it more, but it's needless.