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"The Gradient Function"

I've got some GCSE year 11 Maths c/w to do on "The Gradient Function" and I'm a bit confused as to what I've got to do. Anyone else doing this/done this c/w? It's something to do with drawing graphs for y = x2, y = x, y = x3 and then finding out and analysing the gradient at the tangent. So far, I've got the formulas

g = 3n2 - 3n + 1 for y = x2

Is this right?

I've then got to write about and use the method of difference and say what a great formula it is and how much better it is. :S

How glad I am that I dropped pointless, pointless Maths.

Tomm wrote:
> Helpful as usual...

:):P

Niddle wrote:
> Calculus!

Helpful as usual...

Calculus!

by n do you mean x? I'm just checking your formula...

I'm not to sure if that formula is right, tho' I dont know what you mean by n...

Tbh on this coursework I'm guessing you'd do the y=x2 graph and take the gradient at 1, 2, 3, 4 etc etc then look for a progression between results?

As such;
x.....y.....g
1.....1.....?
2.....4.....?
3.....9.....?
4.....16....?

Since it's year 11, it's probably nothing to do with calculus so I wont bother confusing you...

But i'll tell you its rather simple.

Yeah, you make no sense FF.

The formula for the gradient of a straight line or one particular point on a curved line is:
y = mx + c

y = the current y coordinate
x = the current x coordinate
m = the gradient
c = the y-intercept (where the straight line should cross the y-axis)

Other than that, I don't really understand your explanation. Sorry.

I've got some GCSE year 11 Maths c/w to do on "The Gradient Function" and I'm a bit confused as to what I've got to do. Anyone else doing this/done this c/w? It's something to do with drawing graphs for y = x2, y = x, y = x3 and then finding out and analysing the gradient at the tangent. So far, I've got the formulas

g = 3n2 - 3n + 1 for y = x2

Is this right?

I've then got to write about and use the method of difference and say what a great formula it is and how much better it is. :S