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g = 3n2 - 3n + 1 for y = x2
Is this right?
I've then got to write about and use the method of difference and say what a great formula it is and how much better it is. :S
g = 3n2 - 3n + 1 for y = x2
Is this right?
I've then got to write about and use the method of difference and say what a great formula it is and how much better it is. :S
y = mx + c
y = the current y coordinate
x = the current x coordinate
m = the gradient
c = the y-intercept (where the straight line should cross the y-axis)
Other than that, I don't really understand your explanation. Sorry.
But i'll tell you its rather simple.
I'm not to sure if that formula is right, tho' I dont know what you mean by n...
Tbh on this coursework I'm guessing you'd do the y=x2 graph and take the gradient at 1, 2, 3, 4 etc etc then look for a progression between results?
As such;
x.....y.....g
1.....1.....?
2.....4.....?
3.....9.....?
4.....16....?
> Calculus!
Helpful as usual...
> Helpful as usual...
:):P